Question

assuming full decomposition the volume of CO2 released at STP on heating 9.85g of BaCO3 atomic mass of Ba137 will be​

Answer 1

Answer:

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Explanation:

BaCO

3

→BaO+CO

2

When 197 grams of BaCO

3

is decomposed it forms 22.4 liters of CO

2

If 9.85 grams of BaCO

3

is decomposed it forms X liters of CO

2

.

X=

197

9.85×22.4

=1.12.

Hence volume is 1.12 liters