Assuming fully decomposed the volume of co2 realeased at ntp on heating 9.85 g baco3 will be
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Get the amount of co2 evolved from 9.85 back by, (mol wt of co2/mol wt of baco3)×9.85.
Now 1 mol of co2= 44g of co2= 22.4 liters of con at NTP
Do check with above value of cow and get it's volume.
Now 1 mol of co2= 44g of co2= 22.4 liters of con at NTP
Do check with above value of cow and get it's volume.
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