Question

assuming ideal emf source of 12V in the circuit as shown in figure, the voltmeter reads 8V. the resistance of the voltmeter is​

Answer 1

HEYA GM ❤

★ V = E - Ir

V = 8V , E = 12 , I = V/R = 12/250 = 0.05

★ 8 = 12 - .05 R

★ -4 = -.5 R

★ R = 8 ohm for voltameter...

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Answer 2

voltage drop across 50 ohm will be 12-8 =4

hence current =4/50=0.08

hence 0.08*R =8

where R is total resistance of voltmeter parallel with 200 ohm.

R= 100

hence, (r*200)/(200+r) =100

solve for r which comes out to be 200.