Assuming that a charge on an atom is distributed uniformly in sphere of radius 10 what will be the eletric field of gold atom
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Explanation: Radius should be 10^-10 m. z (atomic no.) for gold= 79
they are saying the charge is accumulated at (centre) sphere of radius 10^-10 m.
and asking what will be the electric field at surface of atom . so,
charge(q) = ze , 79 * 1.6* 10^-19 c = 1.26 *10^-17 c .
-) elctric field = kq/r^2 = 9*10^9* 1.26*10^-17 / (10^-10)^2
= 1.13*10^13 N/C
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