Physics, asked by jayamary104, 5 months ago

assuming that all laws of thermodynamics can be applied to a nucleus the decay of nucleus may be regarded as an

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Answered by Tousif90786
0

Answer:

your answer

Explanation:

radioactive decay is ur answer

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Answered by Afreenakbar
0

This statement is not correct. The decay of a nucleus is a nuclear process, which is governed by the laws of quantum mechanics and not thermodynamics

  • Thermodynamics deals with the relationship between heat, energy, and temperature in macroscopic systems, whereas the decay of a nucleus is a quantum mechanical process that involves the rearrangement of the protons and neutrons within the nucleus.
  • In thermodynamics, an isothermal process is a process that occurs at a constant temperature, but in the case of nuclear decay, the temperature is not a relevant parameter and the process is not thermodynamic.
  • The decay of a nucleus is a nuclear process, which is governed by the laws of quantum mechanics and not thermodynamics

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brainly.in/question/2724479

brainly.in/question/9751178

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