Chemistry, asked by eswarcirc9645, 11 months ago

Assuming that Hund’s rule is violated, the bond order and
magnetic nature of the diatomic molecule B₂ is :
(a) 1 and diamagnetic (b) 0 and dimagnetic
(c) 1 and paramagnetic (d) 0 and paramagnetic

Answers

Answered by kingofself
5

Hund’s rule is violated, the bond order and  magnetic nature of the diatomic molecule B₂ is 1 and diamagnetic.

Explanation:

Hunds rule

  • The electrons fill the orbitals first in the lowest energy, and then it moves to higher energy orbitals, when after the orbitals energy is low are full.
  • This rule states that “all the electrons in individually occupied orbitals have the same spin”. “Every orbital in a sub level is individually occupied before any orbital is doubly occupied”.
  • Maximum multiplicity of hunds rule, more than two orbitals energy are equal. Individually they are occupied by electrons before the pairs were filled by them.

Bond order = (amount of electrons - amount of anti bonding electrons)/2

Given  

Amount of anti bonding electrons is 6.

Amount of electrons is 4.

Bond order = (6-4)/2

Bond order is 1 and unpaired electrons are unavailable so it is diamagnetic.

To learn more;

  1. https://brainly.in/question/5739050
  2. https://brainly.in/question/4008051
Answered by gowriunni2003
0

Answer:

If Hund’s rule is violated, the bond order and  magnetic nature of the diatomic molecule B₂ will be 1 and is diamagnetic, so (A) is the correct answer.

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