Question

Assuming that O2 molecule is spherical in shape with radius 2 A0 (Angstorm) , the percentage of the volume of O2 molecules to the total volume of gas at S.T.P. is :-
(A) 0.09 %
(B) 0.9 %
(C) 0.009 %
(D) 0.045 %

Answer 1

Concept:

Volume of Spherical molecules of oxygen = $\frac{4}{3}*3.14*r^{3}$*Na

Explanation:

Given that,

radius of oxygen molecule (r) = $2*10^{-8} cm$

So,

The volume of oxygen molecule = $\frac{4}{3}*3.14*(2*10^{-8} )^{3}$*Na

Volume =  $33.5*6.023*10^{-24}*10^{23}$ = 20.17 $cm^{3} or mL$

Volume = 0.02017 L

Volume at S.T.P = 22.4 L

Percentage of volume = $\frac{0.02017}{22.4}*100 = 0.09$

Conclusion:

Option A is correct answer of given question

Answer 2

Answer:

0.09%

hope it is helpful

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