Question

Assuming that one-third of the population is tea drinkers and each of 1000 enumeratorstakes a sample of 8 individuals to find out whether they are tea drinkers or not, how manyenumerators are expected to report that five or more people are tea drinkers?​

Answer 1

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here is the answer....

assume that being a tea drinker is like taking a flip of coin.(i.e. either the person drinks tea or not) with the probability of heads being 1/3 and tails being 2/3 now P(X>=5) =P(X=5)+P(X=6)+P(X=7)+P(X=8) = (56*8+28*4+8*2+1)/6561 = 577/6561 =0.087943 so for 1000 trials the number of trials which report greater than or equal to 5 is 1000*P(X>=5) = 87.94 = 88

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