assuming that oxygen atom occupies half of the volume occupied by the water molecule , calculate approximately the diameter of the oxygen atom .
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22400 ml. of oxygen at 273 K temperature and 3-atm pressure = 22400 ×3/1= 67200 ml at STP.
So 224 ml of oxygen at 273 K and 3-atm = 224 ×3= 672 ml at STP
The number of Oxygen molecules present in 22400 ml of gas at STP=N
(where N= Avagadro Number)
Therefore 224 ml of oxygen at 273K and 3-atm pressure will contain =N×672/22400 × N molecules.
=3/100×6.022×10
23
=18.066×10
21
Molecules =1.8066×10
22
molecules
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