Physics, asked by priyumishra1414, 5 months ago

assuming that rate of flow of fluid(V) depends upon radius of tube, coefficient of viscosity and pressure gradient taking value of constant equal to π\8 deduce expression for rate of flow of fluid​

Answers

Answered by anannya61
1

Explanation:

The rate of flow of a liquid Q through a capillary tube depends upon the pressure gradient (lP), radius of the capillary (r), coefficient viscosity η and constant of proportionality is 8π. The equation for the rate of flow of the liquid Q is given by :

Q=8π(M1L0T−2)α(L1)β(M1L−1T−1)γ

Q=M0L3T−1

α=1,β=4,γ=−1

Q=8πηlpr4

Answered by arjavigandhi017
0

Answer:

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