Math, asked by minal30jan, 7 months ago

Assuming that reperitone are not
permitted, how many 5 digit number can be formed
from the six digits 1,2, 3, 5, 7,8​

Answers

Answered by ushanaveen1978
0

Step-by-step explanation:

3 digits formed from 2, 3, 5, 6, 7, 9

Permutation formula =

(n−r)!

n!

=

(6−3)!

6!

3

6

P=66×5×4

=120

2. Numbers less than 400 can start with digits 2 and 3 only.

2×6×6=72

3. Even numbers are 2 and 6 from the given 6 digits.

2×6×6=72

4. Odd numbers are 3, 5, and 7 from the given 6 digits.

6×6×3=108

5. 5 is the only digit from 6 digits have multiples of 5.

6×6×1=36.

HOPE IT IS HELPFUL

Answered by rakeshlic1236
0

Answer:

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Step-by-step explanation:

your answer

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