Assuming that the height distribution of a group is normally, find the mean and
standard deviation if 84% of the men have heights less than 65.2 inches and
68% have heights lying between 62.8 and 65.2 inches
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Mean = 64 inches, SD = 91.2Step-by-
step explanation:
84% of the men have height less than65.
2 inches=> 16% of men have height more than65.2 inches68% have height lying between 65.2 and62.8 inches. =>84-68=16\% men have height lessthan 62.8 inches.=> 65.2 & 62.8 are at equal Distancefrom mean =>mean=(65.2+62.8)/2; =64;
Mean = 64 inches 84\%=>z=1; Z = (Value - Mean) / S * D
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