Physics, asked by dewanand2845, 1 year ago

Assuming that the mass M of the largest stone that can be moved by a flowing river depends on the velocity V of the water,density and acceleration due to gravity g.show the relation

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Answered by simranraj2003abrs
218

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Answered by Haezel
47

Answer:

The relation between velocity, density and acceleration due to gravity is given as \bold{V^{6}} with \bold{d{1}}  and \bold{g^{-3}}

Explanation:

The given question has mass of the largest stone movable by river flow depending upon three factors, their relation can be ruled out using dimensional analysis.

Given are three dependent factors as Velocity V with density d and acceleration due to gravity as g. 

The mass M of the largest stone is directly proportional to the V, d and g

M proportional to V d g, M=\bold{k V^{x} d^{y} g^{z}}

\mathrm{M}=\mathrm{k}\left[\mathrm{L} \mathrm{T}^{-1}\right]^{\mathrm{x}}\left[\mathrm{M} \mathrm{L}^{-3}\right]^{\mathrm{y}}\left[\mathrm{L} \mathrm{T}^{-2}\right]^{\mathrm{z}}

On multiplication, we get \mathrm{M}=\mathrm{k}\left[\mathrm{M}^{\mathrm{y}}\right]\left[\mathrm{L}^{\mathrm{x}-3 \mathrm{y}+\mathrm{z}}\right]\left[\mathrm{T}^{-\mathrm{x}-2 \mathrm{z}}\right

 

\mathrm{k}\left[\mathrm{L} \mathrm{T}^{-1}\right]^{\mathrm{x}}\left[\mathrm{M} \mathrm{L}^{-3}\right]^{\mathrm{y}}\left[\mathrm{L} \mathrm{T}^{-2}\right]^{\mathrm{z}}=\mathrm{k}\left[\mathrm{M}^{\mathrm{y}}\right]\left[\mathrm{L}^{\mathrm{x}-3 \mathrm{y}+\mathrm{z}}\right]\left[\mathrm{T}^{-\mathrm{x}-2 \mathrm{z}}\right]

Now, we have, on comparison  

y = 1

x – 3y + z = 0

x – 3×1 +z = 0

x + z = 3 __________(1)

And,-x -2z = 0__________(2)

Multiply equation 1 with 2 and compare with equation 2

2x + 2z = 6

-x – 2z = 0

x = 6

Thereby, x + z = 3 => 6 + z = 3 => z = -3.

Therefore, \boldsymbol{M}=\boldsymbol{k} \boldsymbol{V}^{6} \boldsymbol{d}^{1} \boldsymbol{g}^{-3} hence, Mass M of the largest stone is proportional to \bold{V^{6}} with \bold{d{1}}  and \bold{g^{-3}}

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