Assuming that V2 is irrational, show that 5V2 is an irrational number
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Assuming that V2 is irrational, show that 5V2 is an irrational number
let us assume that 5+\sqrt{2}
2
is a rational number
5+\sqrt{2}
2
=p/q
\sqrt{2}
2
=p/q-5 (rational-rational=rational)
therefore p/q-5 is rational then \sqrt{2}
2
is also rational
but it is given that \sqrt{2}
2
is irrational in the question
so, it is contradiction to our assumption
then 5+\sqrt{2}
2
is irrational.
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