Question

Assuming the atomic weight of a metal
M to be 56, find the empirical formula
of its oxide containing 70.0% of M.
​

Answer 1

Answer:

The atomic weight of metal is M = 56

metal is 70% by mass and so oxygen is 30% by mass.

let there be n atoms of oxygen per 1 atom of metal.

Then proportion of the masses of metal and oxygen :

56 : n⋊16 = 70 : 30

16 n = 56×

70

30

n =

16

24

= 1.5

There are two atoms of metal for 3 atoms of Oxygen.:

M

2

O

3

Answer 2

Answer:

assume that atomic weight of a metal 'M' to be 56,find the empirical formula of its oxide containing 70% of M

2