Question

assuming the atomic weight of a metalM to be 56,find the emperical formula of its oxide cantaining 70.0% of M.​

Answer 1

Answer:

I hope it's help you

Explanation:

Atomic weight of metal M = 56

in an oxide, metal is 70% by mass

so oxygen is 30% by mass.

let there be n atoms of oxygen per 1 atom of metal.

Then proportion of the masses of metal and oxygen :

56:16n = 70:30

16 n = 56×3070

n = 2416=1.5

There are two atoms of metal for 3 atoms of Oxygen.: M2O3