Question

Assuming the comparable chromosomes in different individuals are genetically dissimilar because of different alleles .how many unique zygotic combinations are possible following fertilization in an organism where n =3 .?

Answer 1

Explanation:

Number of gamete possible in a parent is 2

n

(where n- number of heterozygous allele in parent genotype)

number of zygotes possible are (gamete)X(gamete)

the number of gamete formation possible by parent 1 (AaBBCcDd) - 2

3

= 8 (n=number of heterozygous allele = 3)

the number of gamete formation possible by parent 2 (AAbbCcDD) - 2

1

= 2 (n=number of heterozygous allele = 1)

So, the number of zygotes possible are = gamete of parent 1 X gamete of parent 2

= 8 X 2

= 16

So, the correct answer to the question is '16'.

plzz mark as brainliest