Assuming the density of air to be 1.295 kg m-3,find the fall in barometric height in mm of Hg at a height of 107 m above the sea level. Take density of Mercury = 13.6 × 1000 kg m-3
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Answer:
ρ = 1.295 kg/m³
decrease in the pressure of air = ρ g h = 1.295 * g * 107 Pa
ρ g h = 13.6 * 10³ * g * H
H = decrease in barometric height of mercury
= ρ g h / (13.6*10³ * g) = 10.188 mm
Explanation:
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