Question

Assuming the density of air to be 1.295 kg per m cube ,find the fall in barometric height in mm of Hg at a height of 107 m above the sea level. Take density of mercury =13.6× 1000 kg per m cube.
Answer will be 10 mm of Hg

Answer 1

ρ = 1.295 kg/m³

decrease in the pressure of air = ρ g h = 1.295 * g * 107  Pa

ρ g h = 13.6 * 10³ * g * H

H = decrease in barometric height of mercury
    = ρ g h / (13.6*10³ * g) = 10.188 mm

Answer 2

Answer:

P=hdg

1.295=13.6*10^3*9.8*h

On solving,

h=10mm of hg