Assuming the diameter of the eye pupil to be 2.2mm, calculate the smallest angular separation at which two point objects can be distinctly seen when viewed in light of wavelength 6000 a
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Assuming the diameter of the eye pupil to be 2.2mm, 1.5 mm is the smallest angular separation at which two point objects can be distinctly seen when viewed in light of wavelength 6000 A°
- If the medium is air then value of μ = 1
Also, d = λ/2*μ*sinθ
As θ tends to 0, value of sinθ tends to θ
Therefore, putting values of
- d= 2mm
- λ=6000 A° in the equation, d = λ/2θ
θ = λ/2d
=6000* 10^(-9)/2*2*10^(-3)
=1.5
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