Question

assuming the earth to be homogeneous sphere determine the density of the earth from following data g=9.8m/s G=6.673×10Nm/kg. R=6400

Answer 1

Dear student,

● Answer -
ρ = 5454 kg/m^3

● Explanation -
# Given -
g = 9.8 m/s
G = 6.673×10^-11 Nm/kg
R = 6400 km = 6.4×10^6 m

# Solution -
Volume of earth -
V = (4/3)πR^3
V = (4/3) × 3.12 × (6.4×10^6)
V = 1.1×10^21 m^3

Density of earth can be calculated by -
ρ = M / V
ρ = (6×10^24) / (1.1×10^21)
ρ = 5454 kg/m^3


Hence, density of earth is 5454 kg/m^3.

Hope this helped...

Answer 2

Answer:

p = 5480 kg/m³

Explanation:

G(4/3*π*R³*p) = g*R²

∴ p = 3*g/4πR*G

      = 3×9.8/4×3.14×6.4*10^6×6.67*10^-11

      = 29.4*10^5/536.4

      = 0.05480*10^5

  p = 5480 kg/m³

Hope this helps you!!