Assuming the same pressure in each case, what is the mass of hydrogen required to inflate a balloon to a certain volume V at 100 o C, if 3.5 gm helium is required to inflate the balloon to half the volume V at 25 o C
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Given:
Volume = V
mass of He (w) = 3.5 g
T of Hydrogen = 273 + 100 = 373K
T of Helium = 25 + 272 = 298K
Now,
For Hydrogen, P x V = (w/m)RT
P x V = (w/2) R x 373 ------------ eqn (1)
For Helium, P x V/2 = (w/m)RT
P x V/2 = (35/4) R x 298 ------------- eqn (2)
Solving eqn (1) & (2), we get
mass of hydrogen = 2.8 g
Volume = V
mass of He (w) = 3.5 g
T of Hydrogen = 273 + 100 = 373K
T of Helium = 25 + 272 = 298K
Now,
For Hydrogen, P x V = (w/m)RT
P x V = (w/2) R x 373 ------------ eqn (1)
For Helium, P x V/2 = (w/m)RT
P x V/2 = (35/4) R x 298 ------------- eqn (2)
Solving eqn (1) & (2), we get
mass of hydrogen = 2.8 g
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