Question

assuming the speed of the sound be 340 m/s in air the echo of the building is heard 5sec after the sound is created then find the distance between the building and the listener​

Answer 1

Explanation:

ans-850

v=2d/t(echo )

v=340ms-1

d=?

t=5s

Answer 2

Answer:

Given, (In air)

Velocity V=340m/s

Frequency f=20,000Hz

Wavelegth λ=?

V=f.λ

λ=

F

V

=

20,000

340

=0.017Hz

Also, Given (in Water)

Velocity, V=1480m/s

Frequencyf=20,000Hz

wavelength, λ=?

V=F.λ

λ=

F

V

=

20,000

1480

=0.074Hz