assuming the straight line work as the plane mirror at a point find the image of the point (1,2)in the line x-2y+4=0
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Step-by-step explanation:
let (h,k) be image
(x
1
,y
1
)=(1,2) is given point
comparing x−3y+4=0 with
ax+by+c=0
We have ,
a=1b=−3c=4
By image theorem
a
h−x
1
=
b
k−y
1
=
a
2
+b
2
−2(ax
1
+by
1
+c)
⇒
1
h−1
=
−3
k−2
=
(1)
2
+(−3)
2
−2((1)(1)+(−3)(2)+4)
⇒h−1=
−3
k−2
=
10
−2(1−)
⇒h−1=
10
2
−3
k−2
=
10
2
⇒h=
5
6
k=
5
7
Image =(h,k)=(
5
6
,
5
7
)
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