assuming the water vapour to be a perfect gas , find the internal energy when 1 mole of water at 100 degree Celsius and 1 bar pressure is converted to ice 0 degree Celsius given the enthalpy of fusion of ice : 6.0 kj mol-1 .heat capacity of water :4.2 j/g degree Celsius.
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Answer:
i) The reaction is: H
2
O
(l)
→H
2
O
(g)
We know that,
ΔH=ΔU+Δn
g
RT⟹ΔU=ΔH−Δn
g
RT
So on substituting the given values we get,
ΔU=41kJmol
−1
−
1000
8.3×373
⟹ΔU=37.904 kJ.mol
−1
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