Question

Assuming the xylem tissues through which water rises from root to the branches in a tree to be of uniform cross-section find the maximum radius of xylum tube in a 10 m high coconut tree so that water can rise to the top. (surface tension of water = 0.1N/m, Angle of contact of water with xylem tube= 60∞)

Answer 1

please see attached file....

Answer 2

$\underline\bold{Answer}$

$dgh\pi {r}^{2} = 2\pi \: rs \ \cos( \gamma ) \\ \\ r = \frac{2s \cos( \gamma ) }{dgh} \\ \\ = \frac{2 \times 1 \times 0.5}{ {10}^{3} \times 10 \times 10 } \\ \\ = {10}^{ - 3}$

Thanks !!