Assuming x and y are positive real numbers, simply the following -
(√x)-⅔√y⁴÷√xy-½
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Step-by-step explanation:
(√x)-2/3√y4÷√xy-1)2
=√xy-(1/2)/√x-2)3√y4
=(2√xy-1)/(3√x-2√y4)
=(2√xy-1)/(6√xy4)
=12√x2y5-6√xy4
=6√xy
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