Question

Assuming x and y are positive real numbers, simply the following -
(√x)-⅔√y⁴÷√xy-½​

Answer 1

Step-by-step explanation:

(√x)-2/3√y4÷√xy-1)2

=√xy-(1/2)/√x-2)3√y4

=(2√xy-1)/(3√x-2√y4)

=(2√xy-1)/(6√xy4)

=12√x2y5-6√xy4

=6√xy