Question

Assuming you place a small piece of melting ice in your mouth and eventually all convert from ice at T1= 32.00°f to body temperature, T2=98.60°f. Express these temperature as °C and K and find the change in temperature in both. ​

Answer 1

Answer:

Temperature in two different scales are

$T_1 = 0 ^oC$

$T_1 = 273 K$

$T_2 = 37 ^oC$

$T_2 = 310 K$

$\Delta T = 37^oC$

$\Delta T = 37 K$

Explanation:

As we know that the temperature in degree C and degree K is related with each other as

$^o C + 273 = K$

$^o C = \frac{5}{9}(F - 32)$

now we have

$T_1 = 32^o F$

so we have

$T_1 = \frac{5}{9}(32 - 32) = 0^oC$

$T_1 = 273 K$

for another temperature we have

$T_2 = 98.60 ^oF$

so we have

$T_2 = \frac{5}{9}(98.6 - 32) = 37^oC$

$T_2 = 310 K$

Now change in temperature in degree C

$\Delta T = 37 - 0 = 37 ^oC$

temperature change in kelvin

$\Delta T = 310 - 273 = 37 K$

#Learn

Topic : Temperature conversion

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