Astone dropped from the roof of a building takes 4 s to reach the ground .the hight of the building is
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Heya!!! ✌️✌️
Here is your answer dear.....
initial velocity = 0
time taken = 4s
acceleration = g = 9.8m/s^2
using 2nd equation of motion
s= ut +(1/2)at^2
= (0)(4) +(1/2)(9.8)(4)(4)
= 78.4
So,
distance covered by that stone was 78.4m
I HOPE THIS WILL HELP YOU ✌️✌️
HAVE A GREAT DAY DEAR.....
^_^
Here is your answer dear.....
initial velocity = 0
time taken = 4s
acceleration = g = 9.8m/s^2
using 2nd equation of motion
s= ut +(1/2)at^2
= (0)(4) +(1/2)(9.8)(4)(4)
= 78.4
So,
distance covered by that stone was 78.4m
I HOPE THIS WILL HELP YOU ✌️✌️
HAVE A GREAT DAY DEAR.....
^_^
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