Physics, asked by kundan10424, 7 months ago

Astronaut Nabeela steps out on a space-walk to investigate a circuit on the outside of her module.

She measures the charge flowing in the circuit across a potential difference, V=4.0\ \text VV=4.0 VV, equals, 4, point, 0, space, start text, V, end text, at power, P=0.50\ \text{mW}P=0.50 mWP, equals, 0, point, 50, space, start text, m, W, end text. The total charge measured is Q=2\times10^{-3}\ \text CQ=2×10−3 CQ, equals, 2, times, 10, start superscript, minus, 3, end superscript, space, start text, C, end text.

How much time, ttt, does it take for the charge to move through the circuit?
Note: Let's calculate in the SI unit.​

Answers

Answered by 01mansiarude
1

Answer:

Astronaut Nabeela steps out on a space-walk to investigate a circuit on the outside of her module. ... The total charge measured is Q=2\times10^{-3}\ \text CQ=2×10−3 CQ, equals, 2, times, 10, start superscript, minus, 3, end superscript, space, start text, C, end text.

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