Question

Astronauts land on another planet and measure the density of the atmosphere on the planet surface. They measure the mass of a 500 cm3 conical flask
plus stopper as 457.23 g. After removing the air, the mass is 456.43 g (1 m3 = 1000 litres). What is the best estimate of the density of the air?

Answer 1

Answer:

400 cm3 is answer as 1m3 is 1000 m3

Answer 2

Answer:

$1.6kg/m^{3}$

Explanation:

Given;

The conical flask's volume is 500 $cm^{3}$, and its weight is 457.23 grammes.

After the air is removed, the mass of the conical flask plus the stopper is 456.43 g.

To find:

Density

Solution:

Various materials have different densities in the measurement system. A material's density describes how dense it is. Some substances have a higher density than others. Relative density is a term that can be used to compare the densities of two distinct materials.

A material's density can fluctuate when temperature and pressure change. An object's volume reduces as the amount of pressure applied to it increases, increasing the density of the object. A substance's volume increases as its temperature rises, which causes a reduction in the substance's density.

m= 457.23g-456.43g=0.8g

1g= 0.001 kg

m=0.8g=0.8 × 0.001 kg = 0.0008kg

Volume = $500cm^{3}$

$1cm^{3} =10^{-6} m^{3}$

$V=500cm^{3}=$500×$10^{-6} m^{3}$

Now density,

density=$\frac{mass}{volume}$

d=$\frac{0.0008kg}{0.0005m^{3} }$

=$1.6kg/m^{3}$

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