Asum of money amounts to rs.10648 in 3 yearsand rs.9680 in 2 years.the rate of interest is
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Given Compounded amount = C.A = 10648
in Time= n = 3 years...
Also C.A = 9680 in Time = n = 2 years..
We know that
C.A = P(1+i)^n
Where P = Principal Amount , i = Rate of Interest Per annum , n = number of years/periods
By substituting above information..
we will get...
9680 = P(1+i)^2 ........ Equation (1)
10468 = P(1+i)^3 ....... Equation (2)
Now Divide (2) with (1)... (2)รท (1)
10468/9680 = P(1+i)^3/ P(1+i)^2
1.0814 = (1+i)
1.0814 - 1 = i
0.0814 = i
so i = Rate of Interest Per annum= 0.0814 or 8.14%
in Time= n = 3 years...
Also C.A = 9680 in Time = n = 2 years..
We know that
C.A = P(1+i)^n
Where P = Principal Amount , i = Rate of Interest Per annum , n = number of years/periods
By substituting above information..
we will get...
9680 = P(1+i)^2 ........ Equation (1)
10468 = P(1+i)^3 ....... Equation (2)
Now Divide (2) with (1)... (2)รท (1)
10468/9680 = P(1+i)^3/ P(1+i)^2
1.0814 = (1+i)
1.0814 - 1 = i
0.0814 = i
so i = Rate of Interest Per annum= 0.0814 or 8.14%
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