Math, asked by gprudhviraj9999, 1 year ago

Asum of money at simple interest amounts to rs24000 in 4years .if the rate of interest is increased by 20precent. The same sum amounts to rs 25800 in the same time the original rate of interest us

Answers

Answered by acesolution2017
0

Answer:


Step-by-step explanation:

Given that A sum=24000 in T=4 year;

Rate of interest=?;

Sum is 25800 in the 4 yr when R is increase by 20%;

So new interest is 1.2R;

Amount=Principal + Interest=P(1+\frac{RT}{100})\\;

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Answered by josimagic
0

Answer:

Rate of interest = 241%

Step-by-step explanation:

Simple interest  formula:-

I=\frac{PNR}{100}

P - principle amount

I - simple interest

R - rate of interest

N - number of years

Case 1:- Asum of money at simple interest amounts to rs24000 in 4years

P =  R =  R  N = 4 yeras, A = 24000

Amount A₁=P+\frac{PNR}{100}

</strong>24000<strong>=P+\frac{4PR}{100}

case 2:- .if the rate of interest is increased by 20%

P = ? R=  ?  N = 4 yeras, A = 25800

Amount A₂=P+\frac{PNR}{100}

</strong>25800<strong>=P+\frac{4P(R+20)}{100}

To find the difference in the amounts

A₂ - A₁ = 25800 - 24000 = 1800

P+\frac{4P(R+20)}{100}-[P+\frac{4PR}{100}]=1800

\frac{4P(R+20)}{100}-\frac{4PR}{100}=1800

To find P and R

\frac{4P(R+20-R)}{100}=1800

\frac{4P(20)}{100}=1800

\frac{80P}{100}=1800

P = 2250

To find Rate of interest

P+\frac{4PR}{100}=24000

P+\frac{4*2250*R}{100}=24000

\frac{4*2250*R}{100}=21750

R = 241

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