Asuming the atomic weight of a metal M to be 56,find the empirical formula of oxide captaining 70.0%of M.
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Explanation:
Atomic weight=56,so metal is iron(fe)
Fe=70/56=1.25 =1.25/1.25=1*2=2
O=30/16=1.875=1.875/1.25=1.5*2=3
Therefore, empirical formula of the compound is fe2o3
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