Question

asuming the atomic weight of metal to be 56 find the emparical formula of its oxide containing 70% of m​

Answer 1

Answer:

empirical formula = M2O3

Explanation:

element    %      at mass   % at mass       simple ratio         ratio

Metal         70       56        70/56=1.25     1.25/1.25=1            1x2 = 2

Oxygen     30        16         30/16=1.875   1.875/1.25=1.5       1.5x2=3

therefore, empirical formula = M2O3