Question

At 0.45 porosity the hydraulic conductivity of the sand is 0.010 cm/sec. What is the hydraulic conductivity at n=0.50. a) 0.090 cm/sec b) 0.017 cm/sec c) 0.10 cm/sec d) 0.055 cm/sec Answer A B С ООО с D​

Answer 1

given that

n1=0.450

k1=0.010cm/sec

n2=0.50

hence  according to cozeney - carmen equation

$K=\frac{\gamma_{w}}{c s^{2} \mu} \times \frac{e^{3}}{1+e}$

finally

at n=0.50

e=$\frac{n1}{1-n1}$

e=$\frac{0.50}{1-0.50}$

e=1

hence option  c is correct as 0.8181 is aproximatly equal to 0.8181

Answer 2

Given:

n = 0.450

k1 = 0.010cm/sec

n2 = 0.50

To Find:

the hydraulic conductivity at n =0.50

Solution:

According to Cozeney Carmen equation

   K = УШ/cs²Ч × e³/1+ e

   So, n = 0.50

          e = n1/1-n1

          e = 0.50/ 1- 0.50

          e = 1

Therefore, C is the correct answer as it is approximately close to 0.01.