At 0 degree c and 760 mm hg pressure, a gas occupies a volume of 100 cc. kelvin temperature of the gas is increased by one fifth and the pressure is increased one and a half times. calculate the final volume of the gas.
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A/q V₁ = 100cc = 0.1 L T₁ = 273 P₁ = 760 mm hg = 1 bar
and V₂ = ? T₂ = 273/5 P₂ = 1 x 1 1/2 = 3/2 bar
So from Combined gas law : P₁ V₁ / T₁ = P₂V₂/T₂
⇒ 1 x 0.1 / 273 = 3/2 x V₂ / 273/5
⇒ V₂ = 1 x 0.1 x 273 x 2 / 273 x 5 x 3 ⇒ V₂ = 0.0134 L
Hope my answer is correct.
and V₂ = ? T₂ = 273/5 P₂ = 1 x 1 1/2 = 3/2 bar
So from Combined gas law : P₁ V₁ / T₁ = P₂V₂/T₂
⇒ 1 x 0.1 / 273 = 3/2 x V₂ / 273/5
⇒ V₂ = 1 x 0.1 x 273 x 2 / 273 x 5 x 3 ⇒ V₂ = 0.0134 L
Hope my answer is correct.
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