Question

at 0°c, a gas occupies 22.4l how much hot must be the gas in Celsius and in Kelvin to reach the volume of 25.0l

Answer 1

Answer:

304.6875k , 31.6875°c

Explanation:

it is known to us that,

v varisous to t ( where temperature reepresents t, volume represents s)

0°=273K

It takes 22.4 l in 273 k

then 25l takes( 273 /22.4 ×25)k

=304.6875 k

or, 0°c = 273k

304.6875k - 273 k = 31.6875 °c

now this is the answer in kelvin and Celsius scale.

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Answer 2

Answer:

hope it will help you

Explanation:

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