Question

at 0°c the density of a gaseous oxide at 2 bar is same as that of nitrogen at 5 bar. what is the Molecular mass of the oxide ?​

Answer 1

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Answer 2

$\huge\bigstar\mathfrak\purple{\underline{\underline{SOLUTION:}}}$

Density(d) of the substance at a temperature (T) can be given by the expression,

d= Mp/RT

Now, density of oxide (d1)is given by,

$d1 = \frac{M1p1}{RT}$

Where, M1 and p1 are the mass and pressure of the oxide respectively.

Density of dinitrogen gas (d2), is given by

$d2 = \frac{</u><u>M</u><u>2p2}{</u><u>RT</u><u>}$

Where, M2 & p2 are the mass & pressure of the oxide respectively.

According to the given question,

d1= d2

M1p1= M2p2

Given,

p1= 2 bar

p2= 5 bar

Molecules mass of nitrogen, M2=28g/mol

$now \: M1 = \frac{M2p2}{p1} \\ \\ = > \frac{28 \times 5}{2} \\ \\ = > 70g/ mol$

Hence, the molecular mass of the oxide is 70g/mol.

Krishna ❤️