Question

At 1 atm and 273 K the density of gas, whose molecular weight is 45, is:
(a) 44.8 g/L (b) 11.4 g/L
(c) 2 g/L
(d) 3 g/L
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Answer 1

Answer:

(c)

Explanation:

by PV=NRT the volume of one mole comes out to be 22.4 convert the give weight in kg and put in density=mass/volume where volume comes approx 2.01 so ans is 2g/l

Answer 2

Answer:

c]2g/L

Explanation:

P=DRT/molar mass

by putting values

1=D*0.082*273/45

D=45/22.38

D=2.010g/L