Question

*At 1 bar pressure a gas occupies 10 cc. At what pressure will it occupy 2 cc at constant temperature?*

1️⃣ 5 bar
2️⃣ 10 bar
3️⃣ 15 bar
4️⃣ 20 bar​

Answer 1

Answer:-

Given:

Initial Pressure (P₁) = 1 bar

Initial Volume (V₁) = 10 cc

Final volume (V₂) = 2 cc

Let the final Pressure be P₂.

We know that,

Boyle's law of gases states that at constant temperature the pressure of a gas is inversely proportional to it's Volume.

⟶ P ∝ k/V.

(k is Constant)

⟶ PV = k

⟹ P₁V₁ = P₂V₂

⟹ (1)(10) = P₂ * (2)

⟹ 10/2 = P₂

⟹ 5 bar = P₂

Therefore, the pressure of the gas increases to 5 bar (Option - A).

Answer 2

Given:

gas occupied = 10cc

bar pressure = 1

To Find:

The pressure at which it will occupy to 2ccat a constant temperature

Solution:

the process which will be carried out is an isothermal process.

According to the former of Boyle's law :

P1V1 × P2V2

Therefore,

1×10 = P×2

P2×2 = 10

P2=10/2

P2=5

Answer: the pressure at which it will occupy to CC at a constant temperature is 5 bar