Question

at 1 bar pressure a sample of gas occupies 10 dm3 at constant temperature volume is reduced to 2 dm3 . the pressure of the gas increased by​

Answer 1

Answer:

The answer is 4 bar .

Explanation:

At constant temperature

P1V1 = P2V2 , (Boyle's law)

here P1 = 1 bar, V1 = 10 dm^3, V2 = 2 dm^3

1 × 10 = P2 × 2

P2 = 10/2 = 5 bar

so the pressure of the gas is increased by  5 - 1 = 4 bar.