At 10:00 a.m. two boys start out on their bikes to meet each other from towns located 68 miles apart. At 1:00 p.m. they meet. If one boy traveled 3 miles per hour faster than the other, what was the rate of speed of each boy?
Answers
Answered by
0
Answer: 38.5km/hr and 29.5km/hr.
Step-by-step explanation: Let speed of both boys be x and x+3.
After 3 hrs, distance covered by each = 3x, 3(x+3)
ATQ, 3x +3x+9 = 68
6x = 68-9
x = 59/6 = 9.85 (98.33 rounded off)
Speeds are 38.5km/hr and 29.5km/hr.
Answered by
2
Answer:
9 5/6 and 12 5/6
Step-by-step explanation:
too lazy to type it lol
Similar questions