at 100 degree Celsius gas has 1 ATM.pressure and 10l volume. it's volume at NTP would be
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initial condition
t = 100°C
p = 1atm
v = 10L
at STP
final
t2 = 25°c
p2 = 1atm
v2 = ?
using combine of boyle and charles law
p*v/t = p2v2/t2
v2 = p*v *t2/p2*t
v2 = 1*100*10/1*25= 40L
Answered by
0
Explanation:
At 100℃,P=1atm
V=10L
At NTP, T=20℃
P=1atm
PV=nRT
V∝T
So at NTP temp is less than 100℃ and as the volume is proportional to temperature.
Thus, the volume will be less than 10L as the temperature decreases.
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