Question

At 100 ∘ kw=10−12 , p h ph of pure water at 100 ∘ c 100∘c will be

Answer 1

Answer:

The pH of pure water at 100°C is 6.

Explanation:

$H_2O\rightleftharpoons H^++OH^-$

Ionic product of water at 100°C = $K_w=10^{-12}$

In pure water concentration of hydrogen ions and hydroxide ios are equal.

$K_w=[H^+][OH^-]=[H^+][H^+]=[H^+]^2$

$10^{-12}=[H^+]^2$

$[H^+]=10^{-6} M$

$pH=-\log[H^+}$

$=-\log[10^{-6} M]=6$

The pH of pure water at 100°C is 6.

Answer 2

Answer:

pH of pure water at 100°C is 6

Explanation:

see the above attachment 8-)