Question

At 100℃ the value of pKw is ??


a) 14. b) < 14

c) > 14. d) pH - pOH

Answer 1

What is the value of pKw?

pKw = -log10(10^-14) = 14. pKw of water at 25 degrees C is 14.

Answer 2

Answer:

(a) 14

Explanation:

Ionic product (Kw) = product of $H^{+}$ ions concentration and $OH^{-}$ions

                                 concentration

                      Kw = [ $H^{+}$] x [ $OH^{-}$]

Where Kw is the equilibrium constant. It is also called the dissociation constant or the ionization constant of water.

                       $p^{Kw}$ = $p^{H}$ + $p^{OH}$

That is, for $p^{H}$, it will be less than 14 and for $p^{OH}$, it will be greater than 14.

Therefore, at 100°C  $p^{Kw}$ = 14.