Question

At 11.10 am what will be angle between the hour hand and the minute hand

Answer 1

Answer:At 11:10, the minute hand is at 2 and it makes an angle = 2x30 = 60 deg from 12.

At 11:10, the hour hand is between 11 and 12 and it makes an angle = 11x30+10*30/60 = 330+5 = 335 deg from 12.

At 11:10, the minute and the hour hands make an angle = 335-60= 275 deg between them (reflex angle) or 85 deg (acute).

Answer 2

Answer:

Required angle is 85°

Step-by-step explanation:

Firstly we will find the angle covered by both the hands of the clock in 1 minute.

In 1 hour or 60 minutes, minute hand covers distance$= {360}^{o}$

Therefore in 1 minute the distance covered

$= \frac{ {360}^{o} }{ {60}^{o} } = {6}^{o}$

And in 12 hours,hour hand cover distance $= {360}^{o}$

So,in 1 hour it covers $= \frac{ {360}^{o} }{12} = {30}^{o}$

Therefore in 1 minute,hour hand covers distance

$= \frac{ {30}^{o} }{ {60}^{o} } = \frac{1}{2} = {0.5}^{o}$

(as 1 hour= 60 min)

Now,we got the angles covered by both the hands of clock at 11:10.

So,at 11'o clock the angle is 30° as hour hand moves 30° in 1 hour.

So, difference in hour hand and minute hand in 1 minute

$= {6}^{o} - {0.5}^{o} = {5.5}^{o}$

So,in 10 minutes angle difference $= 10 \times {5.5}^{o}= {55}^{o}$

Now total angle between hour and minute hand at 11:10

$= {30}^{o} + {55}^{o} = {85}^{o}$

Therefore,Required angle is 85°