Question

At 12 cm high object is placed 35 cm in front of the concave mirror that has a focal length of 50 cm determine the location of the image determine the magnification of factor

Answer 1

howdy !!

your answer is ---

Given , u = -35cm , ho = 12cm and
f = -50cm

therefore , by mirror formula

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$
=>
$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$
=>
$\frac{1}{v} = - \frac{1}{50} + \frac{1}{35}$
=> v =
$\frac{350}{3} cm$
hence , image is 350/3 cm away from the mirror and the positive sign show that image is erect and virtual .

now , meginification

m =
$- \frac{v}{u}$
=> m = 10/3


hope it help you