Math, asked by mohamedirfanvia3, 12 hours ago

At 12 noon on certain day the temperature in Delhi was 44℃ . By 5 p.m. that day the temperature fells to 33℃. Find the drop in the temperature.

Ans -​

Answers

Answered by rutu2116
2

Answer:

At Srinagar, Temperature on monday = -5\degree C−5°C

on tuesday, temperature dropped by 2\degree C2°C

therefore, temperature on tuesday = -5\degree C-2\degree C\ =\ -7\degree C−5°C−2°C = −7°C

On wednesday, temperature rose up by 4\degree C4°C

therefore, temperature on wednesday = -7\degree C+4\degree C\ \ =\ -3\degree C−7°C+4°C = −3°C

thus, the temperature on tuesday = -7\degree C−7°C and the temperature on wednesday =-3\degree C−3°C

Answered by sameehatasneem3012
2

Answer:

The drop in temperature was 10degree in 5 hrs

In one hour the temprature goes done till 2 degree

Step-by-step explanation:

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