Question

At 127 c and 1 atm pressure a mixture of a gas contains 0.3 moles of N2 and 0.2 moles of O2 .the vplume of the mixture is

Answer 1

At 127 c and 1 atm pressure a mixture of a gas contains 0.3 moles of N2 and 0.2 moles of O2 .the vplume of the mixture is

answer : 16. 4 litres

explanation : given, pressure of mixture , P = 1 atm

temperature of mixture, T = 127°C = 273 + 127 = 400K

number of mole of gases in the mixture, n = 0.3 mol of N2 + 0.2 mole of O2

= 0.5 mol

from ideal gas equation, PV = nRT

so, V = nRT/P

= 0.5 × 0.082 × 400/1

= 16.4 Litre

hence, volume of the mixture is 16.4 Litres.

Answer 2

Answer:

16.4 mark as brainliest answer please